tg-me.com/RiddlesRepositoryAnswers/193
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Answer to Q178:
I am a three-digit number xyz.
y = 4z
x = y-3
What is xyz?
y = 4z (eqn i)
For eqn i to be valid, that means z be only be 0, 1 or 2.
that is because at 3, y becomes 12 (which is not a single digit)
At 0:
z = 0
y = 4 x 0
y = 0
so, z can also not be 0 because y should be 4x larger than z
At 1:
z = 1
y = 4 x 1
y = 4
and x = y - 3
x = 4 - 3
x = 1
xyz = 141
At 2:
z = 2
y = 4 x 2
y = 8
and x = y - 3
x = 8 - 3
x = 5
xyz = 583
Answer 141 or 583
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